3x^2+7=2x^2-5

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Solution for 3x^2+7=2x^2-5 equation:



3x^2+7=2x^2-5
We move all terms to the left:
3x^2+7-(2x^2-5)=0
We get rid of parentheses
3x^2-2x^2+5+7=0
We add all the numbers together, and all the variables
x^2+12=0
a = 1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·1·12
Δ = -48
Delta is less than zero, so there is no solution for the equation

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